SOLUTION: An amount of 40% acid solution is to be mixed wih enough 10% acid solution to make 25% acid solution. If there are to be 2o liters of the final mixture, how much of each solution s

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Question 363416: An amount of 40% acid solution is to be mixed wih enough 10% acid solution to make 25% acid solution. If there are to be 2o liters of the final mixture, how much of each solution should be mixed together?
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(9681) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = liters of 40% solution needed
Let b = liters of 10% solution needed
given:
.4a = liters of alcohol in 40% solution
.1b = liters of alcohol in 10% solution
.25%2A2+=+.5 = liters of alcohol in final solution
--------------------
(1) %28.4a+%2B+.1b%29%2F2+=+.25
(2) a+%2B+b+=+2
from (1)
(1) .4a+%2B+.1b+=+.5
(1) 4a+%2B+b+=+5
Subtract (2) from (1)
4a+%2B+b+=+5
-a+-+b+=+-2
3a+=+3
a+=+1
and
a+%2B+b+=+2
1+%2B+b+=2
b+=+1
1 liter of 40% solution and 1 liter of 10% solution are needed
check:
(1) %28.4a+%2B+.1b%29%2F2+=+.25
(1) %28.4%2A1+%2B+.1%2A1%29%2F2+=+.25
.5%2F2+=+.25
.5+=+.5
OK

Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
Since 25% is the average of 10% and 40%, it's equal amounts.
Either 1 liter or 10 liters of each, depending on what 2o means.