SOLUTION: one half of a certain even interger plus one fifth of the next consecutive even interger equals 48. Find the two intergers.

Question 348769: one half of a certain even interger plus one fifth of the next consecutive even interger equals 48. Find the two intergers.
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
one half of a certain even integer plus one fifth of the next consecutive even integer equals 48. Find the two integers.
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NOte: All even integers are multiples of 2.
That is what makes them even.
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1st even integer: 2x
2nd: next consecutive even integer 2x+2
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Equation:
(1/2)(2x) + (1/5)(2x+2) = 48
x + (2/5)x + (2/5) = 48
(7/5)x = 240/5
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7x = 240
x = 240/7
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2x is not an even integer
2x+2 is not an even integer
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Please check the problem statement.
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Cheers,
Stan H.
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Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
HI,
*Note: consecutive even integers differ by 2
Let x and (x+2) represent the two integers
.
Write as You Read

.
simplify and solve
Mutiplying each term on both sides of equation by 10

.

x = 68
(x=2) = 70
.
check Your answer
34 + 14 = 48
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