SOLUTION: one half of a certain even interger plus one fifth of the next consecutive even interger equals 48. Find the two intergers.

Question 348768: one half of a certain even interger plus one fifth of the next consecutive even interger equals 48. Find the two intergers.
Found 2 solutions by ewatrrr, checkley77:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
HI,
*Note: consecutive even integers differ by 2
Let x and (x+2) represent the two integers
.
Write as You Read

.
simplify and solve
Mutiplying each term on both sides of equation by 10

.

x = 68
(x=2) = 70
.
check Your answer
34 + 14 = 48
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X/2+(X+2)/5=48
[5X+2(X+2)]/2*5=48
[5X+2X+4]/10=48
[7X+4]/10=48
7X+4=10*48
7X+4=480
7X=480-4
7X=476
X=476/7
X=68 ANSWER FIR TGHE FIRST INTEGER.
68+2=70 ANS. FOR THE SECOND INTEGER.
PROOF:
68/2+70/5=48
34+14=48
48=48
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