SOLUTION: suppose operation # is defined by a#b = (-a)^2 + b What is the value of 6#(2#5)?

SOLUTION: suppose operation # is defined by a#b = (-a)^2 + b What is the value of 6#(2#5)?

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Question 348455: suppose operation # is defined by a#b = (-a)^2 + b
What is the value of 6#(2#5)?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
operation # is defined by a#b = (-a)^2 + b
(2#5)=(-2)^2+5=9
6#9=(-6)^2+9=36+9=45
.
Ed
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