SOLUTION: A 45 foot speaker wire is to be cut into three pieces. One piece is to be 15 feet long. Of the remaining pieces, one must be 2 feet less than 3 times the length of the other. Find
Algebra.Com
Question 345367: A 45 foot speaker wire is to be cut into three pieces. One piece is to be 15 feet long. Of the remaining pieces, one must be 2 feet less than 3 times the length of the other. Find the length of the shorter piece.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
total length = 45
..
first piece 15 feet
let second be x
third piece =30-x
...
30-x=3x-2
+x
30=3x+x-2
30=4x-2
+2
30+2=4x
32=4x
/4
8=x
The lengths are 8, 22, & 15
RELATED QUESTIONS
A 45- foot long speaker wire is to be cut into three pieces. One piece is to be 15 feet... (answered by nerdybill)
A 34-foot-long speaker wire is to be cut into three pieces. One piece is to be 12 feet... (answered by Fombitz)
a 48 cm wire is to be cut into two pieces. One piece must be 10 cm longer than the... (answered by cheesey)
A 48cm wire is to be cut into two pieces. One piece must be 10cm longer than the shorter... (answered by Alan3354)
A 45 foot rope is to be cut into 3 pieces. The second piece must be twice as long as the... (answered by nerdybill,rapaljer)
A 93 foot rope is to be cut into two pieces. One piece must be half as long as the other. (answered by jim_thompson5910)
a piece of wire 10 m long is to be cut into two pieces one of them is 2/3 as long as the... (answered by checkley77)
A piece of wire is 90 cm long. It has to be cut into two piece such that one piece is 2/3 (answered by josgarithmetic)
a piece of wire 10 m long, is to be cut into two pieces, one of them two-thirds as long... (answered by jim_thompson5910)