SOLUTION: please help me solve this: A father is four times as old as his son. In six years time,their combined ages will be 57. How old is the father now?

Question 342360: please help me solve this: A father is four times as old as his son. In six years time,their combined ages will be 57. How old is the father now?
Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let the Father's age be , the son's .
In 6 years their ages are and .
1.
.
.
.

2.
Substitute eq. 1 into eq. 2,

years old
Then from eq. 1,

years old
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
please help me solve this: A father is four times as old as his son. In six years time,their combined ages will be 57. How old is the father now?

Let father's age be F years

Since the father is four times as old as the son, then the son's age is the father's age, or years

In six year's time, the father will be (F + 6) years-old, and the son:

Also, since in 6 year's time, their combined ages will be 57, then we'll have:

Multiplying the equation by it's LCD, 4, we get:

4F + 24 + F + 24 = 228

5F + 48 = 228

5F = 228 - 48

5F = 180

F, or father's age is: or years.
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