SOLUTION: A plane was originally flying at an altitude of x feet when it ascended 2000 feet and then descended 5000 feet. If the plane's altitude after these two chages was 1/3 its original

Question 339382: A plane was originally flying at an altitude of x feet when it ascended 2000 feet and then descended 5000 feet. If the plane's altitude after these two chages was 1/3 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet?
(A) x+2000=1/3(x-3000)
(B) 1/3(x-3000)=x
(C) x+3000=1/3x
(D0 x-7000=1/3x
(E) x-3000=1/3x

Could please provide an explanation of the above problem.

Thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A plane was originally flying at an altitude of x feet when it ascended 2000 feet and then descended 5000 feet. If the plane's altitude after these two chages was 1/3 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet?
----
start: x
ascend 2000: x+2000
decend 5000: x+2000-5000
result: x-3000
Equation
x-3000 = (1/3)x
---
Cheers,
Stan H.
=========================
(A) x+2000=1/3(x-3000)
(B) 1/3(x-3000)=x
(C) x+3000=1/3x
(D0 x-7000=1/3x
(E) x-3000=1/3x

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