SOLUTION: One number is 9 times a first number. A third number is 100 times more than the first number. If the sum of the three numbers is 683, find the numbers

Algebra.Com
Question 335511: One number is 9 times a first number. A third number is 100 times more than the first number. If the sum of the three numbers is 683, find the numbers
Found 2 solutions by Fombitz, nyc_function:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Let's call the numbers A,B and C.



Substitute,



.
.


.
.


Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
Let x = first number
Let 9x = second number
Let 100 + x = third number
x + 9x + 100 + x = 683
Can you take it from here?

RELATED QUESTIONS

One number is 9 times a first number. A third number is 100 more than the first number.... (answered by rfer)
One number is 9 times a first number. A third is 100 more than the first number. If the... (answered by macston)
One number is 4 times a first number. A third number is 100 more than the first... (answered by checkley79)
One number is three times a first number. A third number is 100 more than the first... (answered by advanced_Learner,addingup)
one number is 3 times a first number. a third number is 100 more than the first number.... (answered by Edwin McCravy)
one number is 5 times a first number. a third number is 100 more than the first number.... (answered by Cromlix)
One number is 2 times a first number. A third number is 100 more than the first number.... (answered by Cromlix)
One number is 2 times a first number. A third number is 100 more than the first number.... (answered by TimothyLamb)
ONE number is 3 times a first number. A third number is 100 more than the first number.... (answered by laoman)