SOLUTION: the length and the width of a rectangle are consecutive odd integers. the area of the rectangle is 63 square units. how long is the side of the rectangle.

Question 33268: the length and the width of a rectangle are consecutive odd integers. the area of the rectangle is 63 square units. how long is the side of the rectangle.
Answer by sarah_adam(201) (Show Source): You can put this solution on YOUR website!
I think the question must have been that the length and width are two consequtive even integers:
so let the two consequtive even integers be x and (x+2)
given area of the rectangle is 63 sq units
and the lenght and width of rectangle are two consequtive odd integers
we know
Area = L*W
63 = x*(x+2)
+2x-63 = 0
+9x - 7x - 63 = 0
x(x+9)-7(x+9)=0
(x-7)(x+9) = 0
x = 7 or x = -9 which cannot be as it is negative length
so x = 7
so the dimensions of the rectangle are x = 7 units and x+1 = 7+1 = 8units
but if the problem is for two odd integers only then the integers will be x and x+1
then A = x(x+1)
63 = x^2+x
x^2+x -63 = 0
which doesnt give us finite value of x
So i assumed the dimensions to be two consequtive even integers

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