SOLUTION: Steve has 36 coins consisting of dimes and nickels. If the value of the coins is $3.10, then how many dimes does he have?
Algebra.Com
Question 33109: Steve has 36 coins consisting of dimes and nickels. If the value of the coins is $3.10, then how many dimes does he have?
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
dimes = x
nickels = y
x+y = 36
=> x = 36-y;
10x + 5y = 310
=> 10(36-y) + 5y = 310
=> 360-10y+5y = 310
=> 5y = 50
=> y = 10;
x = 36-y
=> x = 26
Answer: Steve has 26 dimes and 10 nickels
RELATED QUESTIONS
Steve has 36 coins consisting of dimes and nickels. If the value of the coins is $3.10,... (answered by stanbon)
Nick has 35 coins consisting of dimes and nickels. If the value of the coins is $3.10,... (answered by bekah12)
Irving has 35 coins, consisting of only dimes and nickels. If the value of his coins is... (answered by mananth)
teve has 35 coins consisting of dimes and nickels. if the value of the coins is $3.30,... (answered by ewatrrr)
Felix has 40 coins consisting of dimes and nickels. If the value of his coins is $3.80,... (answered by josmiceli)
Carol has 40 coins consisting of dimes and quarters. If the value of the coins is... (answered by checkley77)
John has 36 coins that are nickels and dimes. If the value of the coins is $2.90, how... (answered by brucewill)
Jimmy has coins in his pocket consisting of nickels and dimes. If he has 6 more nickels... (answered by Fombitz)
felix has 35 coins consisting of dimes and nickles. If the value of his coins is $3.30,... (answered by jchambliss)