SOLUTION: movie tickets for an adult and three children cost $20. An adult's ticket costs $2 more than a child's ticket. FInd the cost of the adult's ticket.

Question 328117: movie tickets for an adult and three children cost $20. An adult's ticket costs $2 more than a child's ticket. FInd the cost of the adult's ticket.
Found 2 solutions by jessica43, meay7c:
Answer by jessica43(140) (Show Source): You can put this solution on YOUR website!
To solve this problem, you need to write 2 equations using what you know.
First, you know that movie tickets for an adult and 3 children cost $20. This can be written as:
A + 3C = 20 (where A = price for an adult ticket, C = price for child's ticket)
Second, you know that an adult's ticket costs $2 more than a child's ticket:
A = C + 2
This can also be written as C = A - 2
Now plug the second equation into the first and solve for A:
A + 3C = 20
A + 3(A - 2) = 20
A + 3A - 6 = 20
4A - 6 = 20
4A = 26
A = 6.5
So the price of an adult ticket is $6.50
Answer by meay7c(10) (Show Source): You can put this solution on YOUR website!
Here we are to calculate the cost of an adult ticket.
We know:
1 adult ticket was purchased.
3 children's tickets were purchased.
The adult ticket was $2 more than the children's ticket.

So:
Let x = cost of children's tickets.
Let x + 2 = cost of adult ticket.
Also we know the total cost for all the tickets is $20
Based on this information let's create an equation:
3x + (x + 2) = 20
Now let's simplify.
3x + x + 2 = 20

4x + 2 = 20
4x = 18
x = 4.50
The cost of each of the children's tickets is $4.50, therefore the cost of the adult ticket $6.50 (4.50 + 2).

Let's plug in x to check our solution:
3(4.50) + 4.50 + 2 = 20 Yes !!!
The cost of the adult ticket is $6.50.

Good Luck :-)

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