SOLUTION: Find an equation of the form y-k = a(x-h)[squared] for the parabola that has vertex (1, -5) and contains (-4, 3).

Question 324818: Find an equation of the form y-k = a(x-h)[squared] for the parabola that has vertex (1, -5) and contains (-4, 3).
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find an equation of the form y-k = a(x-h)[squared] for the parabola that has vertex (1, -5) and contains (-4, 3).
---------------------
Vertex is (h,k)
So, h = 1 and k = -5
------
Form:
y+5 = a(x-1)^2
-----
Using (-4,3) you can solve for "a":
3+5 = a(-4-1)^2
a = 8/25
----
Equation:
y + 5 = (8/25)(x-1)^2
==========================
Cheers,
Stan H.
RELATED QUESTIONS
Find an equation of the form y-k = a(x-h)[squared] for the parabola that has vertex (1,... (answered by Fombitz)

Find and equation of the form y-k=a(x-h)^2 for the parabola that has vertex (1,-5) and... (answered by josgarithmetic)

a Parabola has a vertex (-1,5) and contains the point (2,-4). Write an equation of the... (answered by nerdybill)

Write and graph an equation for the parabola that has vertex (-1, 3) and passes through... (answered by lwsshak3)

find an equation in the form y-k=a(x-h)^2 for the parabola with axis of symmetry x=-2and... (answered by lwsshak3)

A parabola of the form y=ax^2+bx+c has a maximum value of y=3. The y-coordinate of the... (answered by josgarithmetic)

Find a parabola equation y-k=a(x-h)^2 if its Vertex(3,2) and it contains the point... (answered by user_dude2008)

a parabola has a vertex v=(6, 4) and a focus f=(6, -1). Enter the equation in the form:... (answered by josgarithmetic)

Show that the quadratic function {{{y=ax^2+bx+c}}} can be written in the form... (answered by fcabanski)