SOLUTION: A chemist needs 240ml of a 50% Solution but only has 32% and 76% solutions to mix. How many mL of each available solution should be mixed together to get 240mL of 50% solution?

Question 301589: A chemist needs 240ml of a 50% Solution but only has 32% and 76% solutions to mix. How many mL of each available solution should be mixed together to get 240mL of 50% solution?
Here is what I have so far:
x+y=240mL
.32x+.76y=240mL*.50
I am not sure if that is the right setup for this problem. Please help me set up a system of linear equation. My solution has to be ordered pair. Thank you
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Looks good.
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