SOLUTION: The perimeter of a rectangle is six times the width. If the length were increased by 4 inches and the width were increased by 7 inches, then the perimeter would be 160 inches. What
Algebra.Com
Question 296571: The perimeter of a rectangle is six times the width. If the length were increased by 4 inches and the width were increased by 7 inches, then the perimeter would be 160 inches. What are the length and the width?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let the width be x
the perimeter = 6x
sum of the lengths = 6x-2x = 4x
each lengh of rectangle = 2x
2*(2x+4)+2*(x+7)=160
4x+8 + 2x+14 =160
^x+22 =160
6x=138
x= 138/3
x= 23 the width
length = 2x = 46
(
RELATED QUESTIONS
The perimeter of a rectangle is six times the width. If the length were increased by 4... (answered by ankor@dixie-net.com)
The perimeter of a rectangle is six times the width. If the length were increased by 4... (answered by jim_thompson5910)
The length of a rectangle is 3 times its width. If the length is increased by 2 inches... (answered by Cromlix)
Need help please.
Translate the problem into a pair of linear equations in two... (answered by ankor@dixie-net.com)
the length of rectangle is 3 times its width. if the length is increased by 2 inches and... (answered by chessace)
may you please help me...."the length of a rectangle is 6 inches more than three times... (answered by Paul)
Solve the problem. The perimeter of a rectangle is 62 m. If the width were doubled and... (answered by edjones)
Solve the problem. The perimeter of a rectangle is 62 m. If the width were doubled and... (answered by ankor@dixie-net.com)
the perimeter of a rectangle is 66m if the width were double and the length were... (answered by mangopeeler07)