SOLUTION: a plane flying the 3020-mile round trip fron city A to city B has a 60 mph tailwind. the flight's point of no return is the point at which the flight time required to return to cit

Question 296477: a plane flying the 3020-mile round trip fron city A to city B has a 60 mph tailwind. the flight's point of no return is the point at which the flight time required to return to city A is the same as the time required to continue to city B.if the speed of the plane in still air is 430 mph, how far from city A is the point of no return? I need to translate this into a pair linear equation in two variables and am stuck. can you help? I can work the problem once i have it in an equation. Thanks.
Found 2 solutions by scott8148, richwmiller:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
why two variables?

time = (distance) / (rate) ___ time back to A equals time to B

x is distance from A to non-return

tailwind is from A to B

A to B distance is half of round trip ___ 3020/2 = 1510

x / (430 - 60) = (1510 - x) / (430 + 60)
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
This problem was posted at least 5 times today.
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