# SOLUTION: A shopkeeper has two types of coffee beans on hand. One type sells for \$3.20 per lb, the other for \$7.80 per lb. How many pounds of the \$3.20 per lb coffee beans must be used in th

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A shopkeeper has two types of coffee beans on hand. One type sells for \$3.20 per lb, the other for \$7.80 per lb. How many pounds of the \$3.20 per lb coffee beans must be used in th      Log On

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 290176: A shopkeeper has two types of coffee beans on hand. One type sells for \$3.20 per lb, the other for \$7.80 per lb. How many pounds of the \$3.20 per lb coffee beans must be used in the mixture to produce 80 lbs of a blend that sells for \$5.04 per lb? Round your answer to 2 decimal places. Answer by richwmiller(9143)   (Show Source): You can put this solution on YOUR website!(3.2*x)+(7.8*y)=(80)*5.04 x+y=80 x=48 y=32