SOLUTION: The chemistry department at a local college decides to stock at least 800 small test tubes and 50 large test tubes. It wants to buy at least 1500 test tubes to take advantage of a

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The chemistry department at a local college decides to stock at least 800 small test tubes and 50 large test tubes. It wants to buy at least 1500 test tubes to take advantage of a      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 28812: The chemistry department at a local college decides to stock at least 800 small test tubes and 50 large test tubes. It wants to buy at least 1500 test tubes to take advantage of a specal price. the department will order at least twice as many small tubes as large.
What would the equations be for this from? I am confused about the equations.

Answer by stanbon(48568) About Me  (Show Source):
You can put this solution on YOUR website!
Let number of large be x>=50
Then number of small is 2x>=800
INEQUALITY:
number of small + number of large >=1500
2x+x>=1500
3x>=1500
x>=500 (number of large test tubes))
2x>=1000 (number of small test tubes)
Cheers,
Stan H.