SOLUTION: Tickets for one show on the Harlem Globetrotters '2006 "Unstoppable" Tour cost $14, $20, or, for VIP seats, $50. So far, five times as many $14 tickets have been sold as VIP ticket

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Tickets for one show on the Harlem Globetrotters '2006 "Unstoppable" Tour cost $14, $20, or, for VIP seats, $50. So far, five times as many $14 tickets have been sold as VIP ticket      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 283125: Tickets for one show on the Harlem Globetrotters '2006 "Unstoppable" Tour cost $14, $20, or, for VIP seats, $50. So far, five times as many $14 tickets have been sold as VIP tickets. The number of $14 tickets is 15 more than the sum of the number of $20 tickets and the number of VIP tickets. Sales of all three kinds of tickets total $11,700. how many of each kind of ticket have been sold?
Answer by richwmiller(9135) About Me  (Show Source):
You can put this solution on YOUR website!

v=vip $50
m= middle price $20
r=regular admission $14
50v+20m+14r=11700
5v=r
r=15+m+v
m = 225, r = 300, v = 60