SOLUTION: The plans for an arpartment complex for 438 apartments with each apartment having one, two, or three bedrooms. There were to be 48 more three-bedroom than one-bedroom apartments an

Question 271380: The plans for an arpartment complex for 438 apartments with each apartment having one, two, or three bedrooms. There were to be 48 more three-bedroom than one-bedroom apartments and the nimber of two bedroom apartments was to be 24 less than 4 times the number of one bedroom apartments . How many apartments of each type were in the plans?
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
Set up:
---------------
Let A = # of 1 bedroom apartments
Let B = # of 2 bedroom apartments
Let C = # of 3 bedroom apartments
Equation 1:
Equation 2:
Equation 3:
Solution:
-----------------
Notice that all the variables are in terms of A.
We can substitute the values in terms of A into equation 1
Equation 1:
Rewrite the equation
Combine like terms
Subtract 24 from both sides
Divide both sides by 6

Now plug 69 into equations 2 & 3 for A
Equation 2:

Equation 3:

Check you answers:
----------------------
Plug your values back into equation 1
Equation 1:

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