SOLUTION: An employee gives a pre-employment evaluation to a large group of applicants. The scores are normally distributed with a mean of 154 and a standard deviation of 7. The employer w

Question 263248: An employee gives a pre-employment evaluation to a large group of applicants. The scores are normally distributed with a mean of 154 and a standard deviation of 7. The employer wants to interview only those applicants who score in the top 5%. What should the cut-off score be for the interviews?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An employee gives a pre-employment evaluation to a large group of applicants. The scores are normally distributed with a mean of 154 and a standard deviation of 7. The employer wants to interview only those applicants who score in the top 5%. What should the cut-off score be for the interviews?
An employee gives a pre-employment evaluation to a large group of applicants. The scores are normally distributed with a mean of 154 and a standard deviation of 7. The employer wants to interview only those applicants who score in the top 5%. What should the cut-off score be for the interviews?
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Find the z-score that determines a 5% right tail.
That z-score is z = invNorm(0.95) = 1.6448..
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Now find the raw score that corresponds to that z-score:
x = zs + u
x = 1.6448*7 + 154
x = 165.51 (This is the cut-off score)
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Cheers,
Stan H.
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