SOLUTION: HEIGHT OF A BULLET: HEIGHT OF A BULLET SHOT INTO THE AIR IS GIVEN BY s(t)= -4.9t^2+ 98t+2, WHERE t IS THE NUMBER OF SECONDS AFTER IT IS SHOT AND s(t) IS IN METERS.

SOLUTION: HEIGHT OF A BULLET: HEIGHT OF A BULLET SHOT INTO THE AIR IS GIVEN BY s(t)= -4.9t^2+ 98t+2, WHERE t IS THE NUMBER OF SECONDS AFTER IT IS SHOT AND s(t) IS IN METERS.

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Question 261598: HEIGHT OF A BULLET: HEIGHT OF A BULLET SHOT INTO THE AIR IS GIVEN BY s(t)= -4.9t^2+ 98t+2, WHERE t IS THE NUMBER OF SECONDS AFTER IT IS SHOT AND s(t) IS IN METERS.

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Stop yelling! Are the guns too loud for you?
BTW since you gave us no other details such as t then the height is s(t) or -4.9t^2+ 98t+2
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