SOLUTION: Find three consecutive integers such that the sum of the first integer and twice the second integer is 542 more than the third integer.
Algebra.Com
Question 261265: Find three consecutive integers such that the sum of the first integer and twice the second integer is 542 more than the third integer.
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
The equation:
Simplify the equation
Subtract 2 from both sides
Subtract X from both sides
Divide both sides by 2
So the numbers are; 271, 272 & 273
Check the answer
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Simplify
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