SOLUTION: three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers

Question 260483: three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers
Found 3 solutions by drk, dabanfield, stanbon:
Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!
Let A be the first number and B be the second number
three times one number equals twice a second number
translates as
(i)
twice the first number is 3 more than the second number
translates as
(ii)
solve (ii) for B to get
(iii)
substitute (ii) into (i) to get
(iv)
distribute to get
(v)
subtract 4A to get
(vi)
divide by -1 to get
(vii)
since A = 6,
Answer by dabanfield(803)   (Show Source): You can put this solution on YOUR website!
three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers
Let x be the first and y the second number.
Then we have:
1.) 3*x = 2*y
2.) 2*x = y + 3
Solve by substitution:
From 2.) we know that y = 2*x - 3
Substitute 2x - 3 for y in equation 1.)
3x = 2*(2x-3)
Solve the above for x. Then calculate y = 2x - 3.
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
three times one number equals twice a second number. twice the first number is 3 more than the second number. find the numbers
------------------
Equation:
3A = 2B
2A = B + 3
-----------------------------
Rearrange:
B = 2A - 3
---
Substitute for "B" and solve for "A":
3A = 2(2A-3)
3A = 4A - 6
A = 6 (1st number)
--------
Since B = 2A-3, B = 2*6-3 = 9 (2nd number)
==============
Cheers,
Stan H.
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