SOLUTION: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle. I have the

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle. I have the      Log On

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Question 254617: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
I have the first equation done, I just need help with the other one. This is what I have:
2L + 2W = 86
Answer by solver91311(17077) About Me  (Show Source):
You can put this solution on YOUR website!


You have already decided that represents the width and represents the length.

Twice the width is . 2cm more than the length is . These two quantities are equal, so:



Then it is a simple matter of slipping in to replace in your perimeter equation.




John