# SOLUTION: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle. I have the

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle. I have the      Log On

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 254617: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle. I have the first equation done, I just need help with the other one. This is what I have: 2L + 2W = 86Answer by solver91311(17077)   (Show Source): You can put this solution on YOUR website! You have already decided that represents the width and represents the length. Twice the width is . 2cm more than the length is . These two quantities are equal, so: Then it is a simple matter of slipping in to replace in your perimeter equation. John