SOLUTION: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
I have the
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Question 254617: Please help me solve this system word problem: The perimeter of a rectangle is 86 cm. Twice the width exceeds the length by 2cm. Find the dimensions of the rectangle.
I have the first equation done, I just need help with the other one. This is what I have:
2L + 2W = 86
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You have already decided that 
represents the width and 
represents the length.
Twice the width is 
. 2cm more than the length is 
. These two quantities are equal, so:
Then it is a simple matter of slipping in to replace in your perimeter equation.
John
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