# SOLUTION: fee simple interest \$300 is borrowed the amount owed after 12 months is \$00 what is the interest rate. 25 is 12% of what number? X + Y =130 6.50X +250Y - 604.5 Graph t

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 Question 250790: fee simple interest \$300 is borrowed the amount owed after 12 months is \$00 what is the interest rate. 25 is 12% of what number? X + Y =130 6.50X +250Y - 604.5 Graph the solutions of equalities 4X+5Y<20 4x-2y<8Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!You have several questions here. Let's take one at a time. QUESTION #1: \$300 is borrowed the amount owed after 12 months is \$00 what is the interest rate. We need I = PRT for this question. P = 300, t = 12 months. Time is measured in years, so t = 1. We don't have interest rate or amount of interest paid back. It appears according to the question that \$300 is paid back after 12 months. Without some R or I info. I can't solve this one. -- QUESTION #2: 25 is 12% of what number? rewrite as 25 = (12/100)*N cross multiply to get 2500 = 12N divide to get N = 208.33 -- QUESTION #3: X + Y =130 6.50X +250Y - 604.5 Don't know if we are solving algebraically or graphing. I will show solve algebraically. I think you mean (i) X + Y =130 (ii) 6.50X +2.50Y = 604.5 step 1: multiply (i) by -2.50 to get -2.5X - 2.5Y = -325 6.50X + 2.50Y = 604.5 step 2: add down to eliminate Y. 4X = 279.5 step 3: solve for X. X = 69.875. step 4: solve for Y. Y = 60.125 -- QUESTION #4: Graph the solutions of equalities (i) 4X + 5Y < 20 (ii) 4X - 2Y < 8 Find x and y intercepts for both equations. (i) X-int = 5 ; Y-int = 4. Plot 5 on the X-axis and 4 on the Y-axis and connect with dashed line. Shade down toward you. (ii) X-int = 2 ; Y-int = -4. Plot 2 on the X-axis and -4 on the Y-axis and connect with dashed line. Shade up away from you. where there is double shading, you have the answer.