SOLUTION: The width of a rectangle is 42 years less than the length. The perimeter of the rectangle is 220 yards. Find the length and width of the rectangle.

Question 242079: The width of a rectangle is 42 years less than the length. The perimeter of the rectangle is 220 yards. Find the length and width of the rectangle.
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Once we've represented the width and length then we can set up an equation.
Let x be the length and x-42 be the width. Now we can set up how it will look.
x+x+(x-42)+(x-42)=220 Combine like terms, we get:
4x-84=220 Add 84 to both sides to get:
4x=304 Divide each side by 4 to result in:
x=76
Now we know the length is 76 yards and the width is 34 yards. To check it out, add these up. Remember there are 4 sides.
RJ Toftness
www.math-unlock.com
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