SOLUTION: A collection of coins consisting of dimes and quarters amounts to $5.35. Twice the number of dimes exceeds the number of quarters by 5. Find the number of each kind of coin.

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Let = number of dimes
Let = number of quarters
given:
(1) (in cents)
(2)
----------------
This is 2 equations and 2 unknowns, so it's solvable
Subtract from both sides of (2)
(2)
Now multiply both sides by
and subtract (2) from (1)
(1)
(2)


and, since
(2)



There are 17 quarters and 11 dimes
check:
(1)



OK