SOLUTION: I need help with figuring out the axis of symmetry, the vertex, and the y-intercept using this quadractic equation: {{{-2(x+2)^2-3}}}

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Question 229241: I need help with figuring out the axis of symmetry, the vertex, and the y-intercept using this quadractic equation: -2%28x%2B2%29%5E2-3
Answer by Alan3354(21608) About Me  (Show Source):
You can put this solution on YOUR website!
I need help with figuring out the axis of symmetry, the vertex, and the y-intercept using this quadractic equation: -2%28x%2B2%29%5E2-3
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The axis of symmetry is x = -2, since it's in standard form.
The vertex is on the axis of symmetry, so f(-2) = -3
Vertex at (-2,-3)
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The y-intercept is at f(0) = -11 --> (0,-11)