# SOLUTION: A number differs from it's square by the average of the number and it's square

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 Question 22673: A number differs from it's square by the average of the number and it's square Answer by rapaljer(4667)   (Show Source): You can put this solution on YOUR website!Let x = the number. = square of the number = difference between a number and its square = average of a number and it's square (add together and divide by 2) The equation should look like this: Multiply both sides of the equation by 2: Set equal to zero, by subtracting x and from each side: Factor out the common factor of x: x= 0 or x= 3 There are two solutions. x=0: The square is 0. The difference of the number and its square is zero, and the average of 0 and its square is also 0. x= 3: The square is 9. The difference of the number and its square is 6, and the average of the number and its square is . Both answers check. R^2 at SCC