Question 214147: For Halloween, Mr. Olowitz bought 8 bags of candy bars and 4 bags of lollipops for a total cost of $51.56. Later that day he realized he didn’t have enough candy and went back to the same store and bought 3 more bags of candy bars and 3 more bags of lollipops at the same prices for a total cost of $23.82. While in the store on his second trip, Mr. Olowitz ran into his neighbor, Mrs. Pinion. If
Mrs. Pinion bought 3 bags of candy bars and 11 bags of lollipops at the same prices, what was her total cost?
Answer by elima4(15)   (Show Source):
You can put this solution on YOUR website! c = candy bars
l = lollipops
----------------------
8c + 4l = 51.56
3c + 3l = 23.82
We need to solve one of the equations for one of the variables,lets solve the second equation for c;
3c + 3l = 23.82
3c = 23.82 - 3l
divide by 3 on each side;
c=7.94 - l
now we have what c = so lets plug that in as c in the first equation;
8(7.94 - l)+4l = 51.56
63.52 - 8l + 4l = 51.56
Collect like terms and subtract 63.52 from both sides;
-4l = -12
l = 3
Now we have price of lollipops, lets plug that into either equation to solve for c;
3c + 3(3) = 23.82
3c + 9 = 23.82
3c = 14.82
c = 4.94
Now lets get Mrs. Pinion's cost;
3(4.94) + 11(3)= 47.82
:)
|
|
|
