SOLUTION: a rectangle is 8 feet longer than it is wide and has an area of 2900 feet squared. What are its dimensions?
Algebra.Com
Question 208072: a rectangle is 8 feet longer than it is wide and has an area of 2900 feet squared. What are its dimensions?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=W+8
LW=2,900
W(W+8)=2,900
W^2+8W-2,900=0
(W-50)(W+58)=0
W-50=0
W=50 ANS. FOR THE WIDTH.
L=50+8
L=58 ANS. FOR THE LENGTH.
PROOF:
50*58=2,900
2,900=2,900
RELATED QUESTIONS
Dimensions of a Rectangle A rectangle is 5 feet
longer than it is wide and has an area... (answered by oberobic)
A rectangular building lot is 8 m longer than it is wide and has an area of 2900 m^2.... (answered by Alan3354)
A rectangular building lot is 8m longer than it is wide and has an area of 2900 m^2. What (answered by Alan3354)
A rectangle is 8 feet longer than it is wide. the area is 65 square feet. find its... (answered by checkley71)
A rectangle is 3 feet longer than it is wide, and its area is 40 square feet. Find its... (answered by checkley71)
A rectangle is 5 feet longer than it is wide, and its area is 66 square feet. Find its... (answered by scott8148)
A rectangle is 5 feet longer than it is wide, and its area is 66 square feet. Find its... (answered by edjones)
A rectangle is 6 inches longer than it is wide. It has an area of 216-squared inches.... (answered by graphmatics)
A rectangle garden is 10ft longer than it is wide. Its area is 875 ft squared. What are... (answered by kmcruz09)