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put this solution on YOUR website!1st number = x
2nd number = y
x - y = 15
3x - 2y = 58
multiply the 1st equation by 2:
2x - 2y = 30
then subtract it from the 2nd equation:
3x - 2y = 58
2x - 2y = 30
-------------- (-)
x = 28
substitute x = 28 into x - y = 15
28 - y = 15
28 - 15 = y
y = 13
so,the larger number is 28