SOLUTION: The height, h (in feet), of a falling object on Mars is given by h=-6t^2+s , where t is the time in seconds and s is the initial height in feet. If an object were dropped from a h

Question 203284: The height, h (in feet), of a falling object on Mars is given by h=-6t^2+s , where t is the time in seconds and s is the initial height in feet. If an object were dropped from a height of 237 feet, how long would it take to travel half the distance to the ground? (Round to two decimal places.)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The height, h (in feet), of a falling object on Mars is given by h=-6t^2+s ,
where t is the time in seconds and s is the initial height in feet.
If an object were dropped from a height of 237 feet, how long would it take to
travel half the distance to the ground? (Round to two decimal places.)
:
half the distance: 237/2 = 118.5 ft
:
-6t^2 + 237 = 118.5
-6t^2 = 118.5 - 237
-6t^2 = -118.5
6t^2 = 118.5; multiplied by -1
t^2 =
t^2 = 19.75
t =
t = 4.44 sec to reach half way down
:
:
Check solution using 4.44 sec
h = -6(4.44^2) + 237
h = -6(19.75) + 237
h = -118.5 + 237
h 118.5
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