SOLUTION: The average hourly wage of employees of a certain company is $9.83. Assume the variable is normally distributed. If the standard deviation is $4.58, find the probability that a
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Question 194810: The average hourly wage of employees of a certain company is $9.83. Assume the variable is normally distributed. If the standard deviation is $4.58, find the probability that a randomly selected employee earns less than $5.43.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The average hourly wage of employees of a certain company is $9.83. Assume the variable is normally distributed. If the standard deviation is $4.58, find the probability that a randomly selected employee earns less than $5.43.
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Find the z-value of 5.43
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z(5.43) = (5.43-9.83)/4.58 = -0.9607
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P(x < 5.43) = P(z < 0.9607) = 0.1684
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Cheers,
Stan H.
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