You can
put this solution on YOUR website!h(t) = -16t^2 + v0t + s0
A potato gun is capable of launching a spud with an initial velocity of 80 feet per second. If the tater takes off from an elevation of 100 feet, how many seconds into its flight will it be at an elevation of 115 feet.
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h(t) = -16t^2 + 80t + 100
At 115 feet:
115 = -16t^2 + 80t + 100
16t^2 - 80t + 15 = 0
t = (10 ± sqrt(85))/4 seconds
One solution for t is on its way up, the other is on its way down.
t = ~ 0.19511 seconds going up
t = ~ 4.80489 seconds going down
You can
put this solution on YOUR website!Simply plug in the given information into:
h(t) = -16t^2 + v0t + s0
.
h(t) = -16t^2 + v0t + s0
115 = -16t^2 + 80t + 100
Moving all terms to the left:
16t^2 - 80t + 15 = 0
Solving the above using the quadratic equation yields:
x = {4.805, 0.195}
.
The tater is at 115 ft at 0.195 secs and again at 4.805 secs after flight.
.
Details of quadratic follows:
| Solved by pluggable solver: SOLVE quadratic equation with variable |
Quadratic equation  (in our case  ) has the following solutons:
For these solutions to exist, the discriminant  should not be a negative number.
First, we need to compute the discriminant :  .
Discriminant d=5440 is greater than zero. That means that there are two solutions:  .
Quadratic expression  can be factored:
Again, the answer is: 4.80488611432322, 0.195113885676778.
Here's your graph:
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