its complement=(90-x) its supplement=(180-x)
acc to the question, (supplement)+38=3(complement) (108-x)+38=3(90-x) 108+38-x=270-3x 146=270-3x+x 146-270=-3x+x -124=-2x 124=2x 2x=124 x=62
Hope this helps, Prabhat