SOLUTION: An express and local train leave GraysLake at 3 P.M and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find t
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Question 193131: An express and local train leave GraysLake at 3 P.M and head for Chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.
Answer by jonvaliente(64) (Show Source): You can put this solution on YOUR website!
Let x=no of hours it takes for the local train
x-1=no of hours it takes for the express train
.
Since speed=distance/time,
speed of the local train = 50/x
speed of the express train =50/(x-1)
If the express train is twice as fast as the local train then:
Multiplying both sides by x*(x-1), we get:
Subtracting 50x from both sides, we get:
Adding 100 on both sides, we get:
Diving both sides by 50 we get:
x=2
So, the local train takes 2 hours to get to Chicago and the express only takes 1 hour to get there.
speed of the local train = 50/2 = 25 mph
speed of the express train = 50/1 = 50 mph
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