# SOLUTION: A consumer electronics company sells 6.7 million MP3 players per month at a price of \$100 apiece; when the price is lowered to \$80, the company sells 10.2 million players per month

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A consumer electronics company sells 6.7 million MP3 players per month at a price of \$100 apiece; when the price is lowered to \$80, the company sells 10.2 million players per month      Log On

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 Question 191544: A consumer electronics company sells 6.7 million MP3 players per month at a price of \$100 apiece; when the price is lowered to \$80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of \$75? I thought I would have to figure out cost ÷ sales. I have gotten myself so confused that I don't know which way is up. I was originally trying to figure it out in a ratio format. 6.7 million/month 10.2 million/month x \$100 each \$80 \$75 =67,000 =127,500 Answer by stanbon(57250)   (Show Source): You can put this solution on YOUR website!A consumer electronics company sells 6.7 million MP3 players per month at a price of \$100 apiece; when the price is lowered to \$80, the company sells 10.2 million players per month. How many MP3 players can the company expect to sell per month at a price of \$75? ------------------------------------------- You want a function where the number of MP3 players is the dependent variable. You have two points: (100, 6.7 million) and (80, 10.2 million) ------------ slope = (10.2-6.7) million/(80-100) slope = 3.5 million/ (-20) = -0.175 million ------------------------------- intercept = ?? 4.7 million = (-0.175 million)*100 + b 4.7 million = -17.5 million + b b = 22.2 million --------------------- Equation: f(x) = (-0.175 million)x + 22.2 million ------------------------------------------ Then f(75) = -0.175 million * 75 + 22.2 million f(75) = 9.075 million (# of MP3s sold if the price is \$75 ------------------------------------------ Cheers, Stan H.