SOLUTION: On Monday, a local hamburger shop sold a combined total of 448 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How man
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Question 188941: On Monday, a local hamburger shop sold a combined total of 448 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Monday?
Found 3 solutions by stanbon, jojo14344, checkley75:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
On Monday, a local hamburger shop sold a combined total of 448 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Monday?
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Equations:
Quantity Eq. : h + c = 448
Quantity Eq. : c = 3h
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Substitute to solve for "h":
h + 3h = 448
4h = 448
h = 112 (# of hamburgers)
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Substitute to solve for "c":
112 + c = 448
c = 336 (# of cheesburgers)
=======================
Cheers,
Stan H.
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
First Condition of Sales for Monday:
CB=3HB , more cheeseburgers were sold, 3 times that of hamburgers sold.
Second condition:
CB + HB = 448
Substitute 1st condition into 2nd condition:
---->
, number of hamburger sold
Go back 1st condition:
, number of cheeseburger sold
Thank you,
Jojo
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
c=3h
c+h=448
3h+h=448
4h=448
h=448/4
h=112 number of hambergers sold.
c=3*112
c=336 number of cheese burgers sold.
Proof
112+336=448
448=448
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