SOLUTION: The position of an object moving in a straight line is given by s=2tsquared-3t, where s is in meters and t is the time in seconds the object has been in motion. How long(to the nea

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Question 186357: The position of an object moving in a straight line is given by s=2tsquared-3t, where s is in meters and t is the time in seconds the object has been in motion. How long(to the nearest tenth) will it take the object to move 6 meters?
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!

s=2tsquared-3t
s=2t^2-3t
.
Set 's' to 6 and solve for 't':
s=2t^2-3t
6=2t^2-3t
0=2t^2-3t-6
Since we can't factor, we must use the quadratic equation.
Doing so yields:
t = {2.6, -1.1}
We can toss out the negative solution leaving
t = 2.6 seconds
.
Details of quadratic follows:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=57 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2.63745860881769, -1.13745860881769. Here's your graph:

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