SOLUTION: A collection of dimes and nickels is worth $8.40. There are 106 coins in all. How many of each are there?

Question 185976: A collection of dimes and nickels is worth $8.40. There are 106 coins in all. How many of each are there?
Answer by MissionPossible(18) (Show Source): You can put this solution on YOUR website!
suppose there are N nickels and D dimes.
N + D = 106 (There are 106 coins in all.)
1 nickel = 5 cents.
1 dime = 10 cents.
5*N + 10*D = 840 ($8.40 = 840 cents)
N + D = 106 -------(1)
N = (106 - D)
5*N + 10*D = 840 ---------(2)
5*(106-D) + 10*D = 840
530 - 5*D + 10*D = 840
5*D = 840 - 530
5*D = 310
D = 310/5 = 62
Eq(1) N + D = 106
N + 62 = 106
N = 106 - 62
N = 44
Then , there are 62 dimes , 44 nickels. Ans.

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