SOLUTION: a garage owner wants to fill a 55 gallon drum with a 20 percent winter mixture of antifreeze for his customers. how many gallons of 100 percent antifreeze should he mix with some 1

Question 184965: a garage owner wants to fill a 55 gallon drum with a 20 percent winter mixture of antifreeze for his customers. how many gallons of 100 percent antifreeze should he mix with some 10 percent antifreeze mixture in order to fill the drum
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let x = the number of gallons of pure (100%) antifreeze needed to mix with the 10% antifreeze mixture to obtain 55 gallons of 20% antifreeze mixture.
x + (55-x)(0.1) = 55(0.2)
x + 5.5 - 0.1x = 11
0.9x + 5.5 = 11
0.9x = 5.5
x = 6.11 (approx) gallons of pure antifreeze.
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