SOLUTION: A migrating elephant herd started moving at a rate of 6 miles per hour. ONe elephant stood still and was left behind. Then this stray elephant sensed danger and began running at a

Question 177979This question is from textbook Algebra 1
: A migrating elephant herd started moving at a rate of 6 miles per hour. ONe elephant stood still and was left behind. Then this stray elephant sensed danger and began running at a rate of 10 miles per hour to reach the herd. The Stray caught up in 5 min.
How long (in hours) did the Stray run to catch up? How far did it run? This question is from textbook Algebra 1

Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
ok!!! for the 5 minutes that the lone elephant traveled at 10mph he traveled
:
d=r*t
:
d=10(1/12)......5 min = 1/12 of an hour
:
d=10/12=5/6 of a mile
:
we already answered how long he ran in hours 1/12 of an hour(5min)
:
btw the herd traveled for 1/3 mile while he stood still
:
the way we know this is because the herd traveled at 6mph during the 5 minutes he was catching up so they traveled 6(1/12)=1/2mi during that 5 minutes. Since the lone elephant traveled 5/6 mile to catch up then 5/6-3/6 of a mile=2/6=1/3 of a mile was what the herd traveled while he was still.
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