SOLUTION: Multiply as required and collect terms
( x – 4)(2x2 + 4) + ( x + 4)(x3 – 1) – ( x2 – x – 1)
Algebra.Com
Question 176996: Multiply as required and collect terms
( x – 4)(2x2 + 4) + ( x + 4)(x3 – 1) – ( x2 – x – 1)
Answer by colliefan(242) (Show Source): You can put this solution on YOUR website!
( x – 4)(2x2 + 4) + ( x + 4)(x3 – 1) – ( x2 – x – 1)
{( x – 4)(2x2 + 4)} + {( x + 4)(x3 – 1)} {– ( x2 – x – 1) }
First, simplify the last of these 3 sections so we don't forget that the minus sign applies to all 3 of the last terms and that if we are subtracting a negative x, it is really adding x.
( x – 4)(2x^2 + 4) + ( x + 4)(x^3 – 1) – x^2 + x + 1
Then multiply each term in the binomials by the other terms. Watch the signs.
x*2x^2 + x*4 -4*2x^2 -4*4 + x*x^3 - x*1 + 4*x^3 – 4*1 – x^2 + x + 1
2x^3 + 4x - 8x^2 - 16 + x^4 - x + 4x^3 – 4 – x^2 + x + 1
Reorganizing the terms:
x^4 + 2x^3 + 4x^3 - 8x^2 – x^2 + 4x - x + x - 16 + 1– 4
Now, combine like terms:
x^4 + 6x^3 - 9x^2 + 4x - 19
RELATED QUESTIONS
Multiply as required and collect terms
( x – 4)(2x^2 + 4) + ( x + 4)(x^3 – 1) – ( x^2 –... (answered by jim_thompson5910)
I was instructed to "multiply as required and collect terms" I am really not sure what it (answered by vleith,solver91311)
Multiply and collect terms... (answered by checkley77)
Multiply: (x + 1)(x3 + 7x2 + 5x + 4)
(answered by Alan3354,Cromlix)
I believe I have done this one right but if someone could please confirm?
Multiply as... (answered by monika_p)
1+ 2/x+ 4/x2+ 8/x3
__________________
1-... (answered by Fombitz)
. Evaluate 1 + x + x2/2! + x3/3! +
x4/4! + .......
(answered by tommyt3rd)
Can you please help with this one?
(16 - x2)/
(x3 - 2x2 - 8x)
So far I have:... (answered by edjones)
Simplify (Show work):
x-1/x^2+1 * x^4-1/(x-1)^2 * x^2-1/x^4-2x^2+1
x-1/x^2+1 *... (answered by romenoodle)