SOLUTION: Find two numbers whose sum is 64 and whose difference is 4 . (We will call the two numbers x and y .) I am trying to help my son with some school work but I am not havin

Question 176748: Find two numbers whose sum is 64 and whose difference is 4 .
(We will call the two numbers x and y .)

I am trying to help my son with some school work but I am not having much luck can yo help?

Found 2 solutions by checkley75, Mathtut:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
X+Y=64
X-Y=4 OR X=4+Y
NOW REPLACE X WITH(4+Y) IN THE FIRST EQUATION
(4+Y)+Y=64
4+2Y=64
2Y=64-4
2Y=60
Y=60/2
Y=30 ANS.
X-30=4
X=30=4
X=34 ANS.

Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
ok our two numbers are x and y
:
x+y=64....eq 1
x-y=4.....eq 2
:
rewrite eq 2 to x=4+y and plug that value into eq 1
:
(4+y)+y=64
:
2y=60.....subtracted 4 from both sides and combined like terms
:
divided by 2 on each side to isolate variable y
:
x=4+y
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