SOLUTION: A chemist wants to make 200 mL of acid solution with a concentration of 48%. He wants to make this from two solutions with 60% and 40% concentration respectively. How much of each

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Question 172437: A chemist wants to make 200 mL of acid solution with a concentration of 48%. He wants to make this from two solutions with 60% and 40% concentration respectively. How much of each solution should he use? (Hint: The amount of acid in the final mixture is the sum of the amounts contributed by each solution.)
Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website!
so lets call the amounts of 40% and 60% solutions a and b
:
a+b=200.............eq 1
.4(a)+.6(b)=.48(200)..eq 2
:
lets rewrite eq 1 a=200-b and plug a's value into eq 2
:
.4(200-b)+.6b=96
:
80-.4b+.6b=96
:
.2b=16
:
ml of 60% solution
:
ml of 40% solution