SOLUTION: Find the three consecutive odd integers such that the product of the first and third integers is 4 less than the square of the second integer.

Question 165701: Find the three consecutive odd integers such that the product of the first and third integers is 4 less than the square of the second integer.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Find the three consecutive odd integers such that the product of the first and third integers is 4 less than the square of the second integer
:
The three odd integers: x, (x+2), (x+4)
:
1st*3rd = 2nd^2 less 4
x*(x+4) = (x+2)^2 - 4
:
x^2 + 4x = x^2 + 4x +4 - 4
:
x^2 + 4x = x^2 + 4x; no kidding!
:
No unique solution, any value for x will make the equation happy
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