SOLUTION: Five times the smallest of three consecutive odd integers is ten more than twice the largest. Find the integers.

SOLUTION: Five times the smallest of three consecutive odd integers is ten more than twice the largest. Find the integers.

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Question 159597This question is from textbook Intermediate Algebra
: Five times the smallest of three consecutive odd integers is ten more than twice the largest. Find the integers. This question is from textbook Intermediate Algebra

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
5x=10+2(x+4)
5x=10+2x+8
5x-2x=18
3x=18
x=18/3
x=6 answer for the smallest integer.
Proof:
5*6=10+2(6+4)
30=10+2*10
30=10+20
30=30
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