SOLUTION: Write and solve a system of3. An embossing shop etches metal with acid solutions. The owner is discussing a certain job with the job supervisor, and they decide to use 30 ounces o

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Write and solve a system of3. An embossing shop etches metal with acid solutions. The owner is discussing a certain job with the job supervisor, and they decide to use 30 ounces o      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 159180: Write and solve a system of3. An embossing shop etches metal with acid solutions. The owner is discussing a certain job with the job supervisor, and they decide to use 30 ounces of a 40% solution. Upon checking the acid solution supplies, the supervisor has found some 25% acid solution and some 50% acid solution, but there is no 40% acid solution. The owner explains to the supervisor how the two existing solutions can be mixed to obtain a 40% acid solution. How much of each solution is needed? equations for a given model / word problem:
Answer by ankor@dixie-net.com(12704) About Me  (Show Source):
You can put this solution on YOUR website!
Write and solve a system of3. An embossing shop etches metal with acid solutions. The owner is discussing a certain job with the job supervisor, and they decide to use 30 ounces of a 40% solution. Upon checking the acid solution supplies, the supervisor has found some 25% acid solution and some 50% acid solution, but there is no 40% acid solution. The owner explains to the supervisor how the two existing solutions can be mixed to obtain a 40% acid solution. How much of each solution is needed? equations for a given model / word problem:
:
Let x = amt of 50% solution
It said the total has to be 30 oz, therefore:
(30-x) = 25% solution
:
Write a decimal equiv equation:
.50x + .25(30-x) = .40(30)
:
.50x + 7.5 - .25x = 12
;
.50x - .25x = 12 - 7.5
:
.25x = 4.5
x = 4.5%2F.25
x = 18 oz of 50% solution
and
30 - 18 = 12 oz of 25% solution
;
:
Check solution in original equation:
.5(18) + .25(12) = .4(30)